Answer to Question #325806 in General Chemistry for Nad

Question

Using the reaction on below:

Sn(s) + Pb²+ (aq) → Sn²+ (aq) + Pb(s)

a. Write the oxidation and reduction half reaction.

b. Construct a cell diagram.

c. Write the overall equation of the reaction.

d. Solve for the cell potential.

Answer 1

a. Pb²⁺ + 2e^- = Pb, E⁰ = -0.13 V

Sn = Sn²⁺ + 2e^-, E⁰= 0.14 V

b. Sn(s) | Sn²⁺ || Pb²⁺ | Pb(s)

c. Sn(s) + Pb²+ (aq) → Sn²+ (aq) + Pb(s)

d. E_cell = 0.14 - (-0.13) = 0.27 V