Answer to Question #325715 in General Chemistry for Naya

Question #325715

If a 15.6 g object requires 836.8 J of heat to raise its temperature by 21.0°C, what is the specific heat of the object?

Expert's answer

q = m × C × ∆T

C = q / (m × ∆T) = 836.8 J / (15.6 g × 21.0°C) = 2.55 J/g °C

Learn more about our help with Assignments: Chemistry

No comments. Be the first!

Who Can Help Me with My Assignment

There are three certainties in this world: Death, Taxes and Homework Assignments. No matter where you study, and no matter…
How to Finish Assignments When You Can’t

Crunch time is coming, deadlines need to be met, essays need to be submitted, and tests should be studied for.…
How to Effectively Study for a Math Test

Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…