2. A 0.2719 g sample containing πΆππΆπ3 reacted with 20.00 mL of 0.2254 M HCl. Given that HCl was excess. The excess HCl required exactly 20.00 mL of 0.1041 M NaOH to reach the end-point using phenolphthalein indicator.
Determine percentage purity of πΆππΆπ3 in the sample. The reaction involved is
πΆππΆπ3(π ) + 2π»πΆπΌ(ππ) β πΆππΆπΌ2(ππ) + 2π»2O(l)
The titration reaction is
π»πΆ(ππ) + NaOH(aq) ππCl(ππ) + π»2π(l)
The answer to your question is provided in the image:
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