Answer to Question #325675 in General Chemistry for Raphael

Question #325675

2. A 0.2719 g sample containing πΆπ‘ŽπΆπ‘‚3 reacted with 20.00 mL of 0.2254 M HCl. Given that HCl was excess. The excess HCl required exactly 20.00 mL of 0.1041 M NaOH to reach the end-point using phenolphthalein indicator.

Determine percentage purity of πΆπ‘ŽπΆπ‘‚3 in the sample. The reaction involved is

πΆπ‘ŽπΆπ‘‚3(𝑠) + 2𝐻𝐢𝐼(π‘Žπ‘ž) β†’ πΆπ‘ŽπΆπΌ2(π‘Žπ‘ž) + 2𝐻2O(l)

The titration reaction is

𝐻𝐢(π‘Žπ‘ž) + NaOH(aq) π‘π‘ŽCl(π‘Žπ‘ž) + 𝐻2𝑂(l)


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2022-04-10T20:31:01-0400

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