Answer to Question #325670 in General Chemistry for Rex

Question

Calculate the molarity of the 19.60 g/L FeSO4(NH4)SO4.6H2O, standard

solution.

Answer 1

19.60 g of solute in 1 L of solution

n(FeSO₄(NH₄)SO₄•6H₂O) = m(FeSO₄(NH₄)SO₄•6H₂O) / Mr(FeSO₄(NH₄)SO₄•6H₂O) = 19.60 g / 392 g/mol = 0.05 mol

C = 0.05 mol / 1 L = 0.05 mol/L