Answer to Question #325666 in General Chemistry for Student43

Question

I’m one experiment 8.66g of NO is mixed with 5.03 g of O2 what is the limiting reactant

Answer 1

2NO + O₂ = 2NO₂

n(NO) = m(NO) / Mr(NO) = 8.66 g / 14.01 g/mol = 0.618 mol

n(O₂) = m(O₂) / Mr(O₂) = 5.03 g / 16.00 g/mol = 0.314 mol

2 mol NO react with 1 mol O₂

NO is limiting reactant