On complete combustion, 0.246 g of an organic compound gave 0.198 g of CO2 and 0.1014 g of H2O. What is the ratio of carbon and hydrogen atoms in the compound?
Mass fraction of C in CO₂ = 12/(12 + 16×2) = 12/44
Mass fraction of H in H₂O = 1×2/(1×2 + 16) = 2/18
Mass of C in the compound = Mass of C in CO₂ = (0.246 g) × (12/44) = 0.0671 g
Mass of H in the compound = Mass of H in H₂O = (0.1014 g) × (2/18) = 0.0113 g
In the compound, the ratio of carbon and hydrogen atoms
= Mole ratio C : H
= (0.0671/12) : (0.0113/1)
= 0.00559 : 0.0113 …… (0.00559 is the smallest number)
= (0.00559/0.00559) : (0.0113/0.00559)
= 1 : 2
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