what is the volume of a gas at 50.0 degrees Celsius and 0.80 atm, if there are 0.75 moles of the gas present?
PV = nRT
V = nRT / P
T = 50 °C = 323.15 K
P = 0.80 atm = 81.06 kPa
V = ( 0.75 mol * 8.314 kPa L/mol K * 323.15 K ) / 81.06 kPa = 24.86 L
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