Answer to Question #325222 in General Chemistry for greg

Question

how many moles of PCl5 can be produced from 58.0 g of Cl2 (excess P4)

Answer 1

m(Cl₂) = 58.0 g;

M(Cl₂) = 71 g/mol;

n(Cl₂) = m(Cl₂)/M(Cl₂) = 58/71 = 0.817 mol;

P₄ + 10Cl₂ = 4PCl₅;

Since P₄ is the excess reagent, then by the chemical reaction:

n(PCl₅) = 4/10 * n(Cl₂) = 4/10 * 0.817 = 0.327 mol.

Answer: 0.327 mol.