Calculate the molarity of a solution prepared by dissolving 250.0 g of Ca(NO3)2 in enough water to make 3.50 L of solution.
a
5.34 M
b
0.45 M
c
1.52 M
d
71.4 M
M(Ca(NO3)2=40+2(14+16x3))=40+144=164 g/mol
n(Ca(NO3)2)=250/164=1.524mol
c(Ca(NO3)2)=1.524/(3.5)=0.45 mol/l
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