Answer to Question #323963 in General Chemistry for LOVE_21

Question

Acetone, C3H6, is the main ingredient of nail polish remover. A solution is made up

by adding 35.OmL of acetone (d=0.790g/mL) to 50.0mL of ethyl alcohol, C2H60

(d=0.789g/mL). Assuming volumes are additive, calculate (a) the mass percent of

acetone in the solution. (b) the volume percent of ethyl alcohol in the solution. (c) the

mole fraction of acetone in the solution.

Answer 1

density = m / V

m (C₃H₆) = 35 x 0.79 = 27.7 g

m (C₂H₆O) = 50 x 0.789 = 39.5 g

a) Mass percent acetone in the solution = (100 x 27.7) / (27.7 + 39.5) = 41%

b) the volume percent of ethyl alcohol in the solution: (100 x 50) / (35 + 50) = 59%

(c) n = m / M

M (C₃H₆) = 42.1 g/mol

M (C₂H₆O) = 46.1 g/mol

n (C₃H₆) = 27.7 / 42.1 = 0.66 mol

n (C₂H₆O) = 39.5 / 46.1 = 0.87 mol

The mole fraction of acetone in the solution: 0.66 / (0.66 + 0.87) = 0.43