Question

Calculate the molality of a 6.55 kg sample of a solution of the solute CH²Cl²dissolve in the solvent acetone C³H0O if the sample contains 876 g of methylene chloride

Answer 1

Moles of methylene chloride = $\dfrac{mass}{MM}=\dfrac{876g}{84.93g/mol}$ =10.314mol

Volume of solution = \dfrac{mass of mixture}{density of acetone}

=$\dfrac{6550g}{0.784g/cm^3} = 8354.59cm^3$

Molarity og solution;

10.314 mole $\to$ 8354.59cm3

? $\to$ 1000cm3

=$\dfrac{10.314mol x 1000cm^3}{8354.59cm^3} = 1.23M$