Answer to Question #323775 in General Chemistry for tori

General Chemistry

Question #323775

A 11.38 L balloon contains 0.63 mol of air at 185.50 kPa pressure. What is the temperature of the air in the balloon?

Expert's answer

P₁V₁/T₁ = P₂V₂/T₂

P₁*6.3/T₁ = 1.5P₁*V₂/0.75T₁

6.3 = 2V₂

V₂ = 6.3 / 2 = 3.15 (L)

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