A gas at a temperature of 127 0C is heated in a freely expandable container until its volume doubles. What is the new temperature of the gas?
T1 = 127 C = 400 K;
V2 = 2 * V1;
V1/T1 = V2/T2 or V1/T1 = 2 * V1/T2;
T2 * V1 = 2 * V1 * T1;
T2 = 2 * V1 * T1/V1 = 2 * T1 = 2 * 400 = 800 K = 527 C.
Answer: 527 C.
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