Calculate the number of grams of solute necessary to prepare a 500.0 mL of a 0.10M
sodium hydroxide solution.
CM = n / V
n (NaOH) = CM / V = 0.10 / 0.5000 = 0.2 mol
n = m / M
M (NaOH) = 40 g/mol
m (NaOH) = n x M = 0.2 x 40 = 8 g
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