Aqueous hydrobromic acid (HBr) will react with solid sodium hydroxide (NaH) to produce aqueous sodium bromide (NaBr) and liquid water (H, 0).
Suppose 75.2 g of hydrobromic acid is mixed with 14. g of sodium hydroxide. Calculate the maximum mass of sodium bromide that could be produced by the
chemical reaction. Be sure your answer has the correct number of significant digits.
HBr + NaOH = NaBr + H2O
n(HBr) = m(HBr) / Mr(HBr) = 75.2 g / 80.91 g/mol = 0.93 mol
n(NaOH) = m(NaOH) / Mr(NaOH) = 14.0 g / 40.0 g/mol = 0.35 mol
NaOH is limiting reactant
n(NaBr) = n(NaOH) = 0.35 mol
m(NaBr) = n(NaBr) × Mr(NaBr) = 0.35 mol × 102.894 g/mol = 36.0 g
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