Answer to Question #323255 in General Chemistry for Courtney

Question

Gaseous butane (CHa (CH,), CHg) will react with gaseous oxygen (0.) to produce gaseous carbon dioxide (CO,) and gaseous water (H, O). Suppose 4.1 g

of butane is mixed with 19.7 g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the

correct number of significant digits.

Answer 1

m(C₄H₁₀) = 4.1 g;

M(C₄H₁₀) = 58 g/mole;

n(C₄H₁₀) = m(C₄H₁₀)/M(C₄H₁₀) = 4.1/58 = 0,071 mol;

m(O₂) = 19.7 g;

M(O₂) = 32 g/mol;

n(O₂) = m(O₂)/M(O₂) = 19.7/32 = 0.616 mol;

So, O₂ is the excess reagent and C₄H₁₀ is the limited reagent;

2C₄H₁₀ + 13O₂ = 8CO₂ + 10H₂O;

By the chemical reaction:

n(H₂O) = 10/2 * n(C₄H₁₀) = 5 * n(C₄H₁₀) = 5 * 0.071 = 0.355 mol;

M(H₂O) = 18 g/mol;

m(H₂O) = n(H₂O) * M(H₂O) = 0.355 * 18 = 6.4 g.

Answer: 6.4 g.