Answer to Question #323220 in General Chemistry for Nswa

Question

How many grams of NH

4

Cl

NH4Cl will be formed by this reaction?

Answer 1

Moles NH3 gas remaining at end of reaction:

Starting moles NH3 = 6.90 g NH3 x 1 mol NH3/17 g = 0.406 moles NH3

6.90 g HCl x 1 mol HCl/36.5 g x 1 mol NH3/mol HCl = 0.189 moles NH3 used up to react with the HCl

moles NH3 remaining = 0.406 - 0.189 = 0.217 moles NH3 remaining

Using the ideal gas law to find the pressure of the gas remaining:

PV = nRT

P = nRT/V = (0.217)(0.0821 Latm/Kmol)(298K)/2.00 L

P = 2.65 atm