Answer to Question #323071 in General Chemistry for soph

Question

. During a serial dilution, you use 15.0 mL of a standard solution and dilute it to 1.35 L twice. What is the final concentration if the standard solution had a concentration of 0.500 M? 

Answer 1

V₁ = 15 mL = 0.015 L;

V₂ = 1.350 L;

C₁ = 0.500 M;

n = C₁ * V₁ = 0.500 * 0.015 = 0.0075 mol;

C₂ = n/V₂ = 0.0075/1.350 = 0.0056 M.

Answer: 0.0056 M.