Determine the empirical formula if a compound is made up of 14.0 g Nitrogen and 8.00 g Oxygen.
N2O
m(N) = 14 g
Mr(N) = 14
m(O) = 8 g
Mr(O) = 16
N : O = n(N)/n(O) = m(N)/Mr(N) : m(O)/Mr(O)
N : O = 14/14 : 8/16 = 1 : 0,5 => *2 => N : O = 2:1 => N2O
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