Answer to Question #322662 in General Chemistry for Shannee

Question

Calculate the ∆H for the reaction:

CS2 + 2 O2 CO2 + 2 SO2

Given:

∆Hf CO2 = -393.5 kJ/mol

∆Hf SO2 = -296.8 kJ/mol

∆Hf CS2 = 87.9 kJ/mol

Answer 1

∆H₃= ∆H₁ - ∆H₂

= (-393.5 + -296.8×2) - 87.9

= -987.1 - 87.9

= -1075kJ/mol