Calculate the Kc of the reaction below if the equilibrium concentrations of Ag and IO3 are both 1.78×10-⁴M
AgIO3 <=> Ag+ + IO3-
1 - 1.78*10-4 1.78*10-4 1.78*10-4
"K_c = ~\\dfrac {[Ag^+][IO_3^-]}{[AgIO_3]}=~\\dfrac {(1.78*10^{-4})^2}{1-1.78*10^{-4}}=~ 3.17*~10^{-8}"
Answer: 3.17*10-8
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