Question

Calculate the Kc of the reaction below if the equilibrium concentrations of Ag and IO3 are both 1.78×10-⁴M

Answer 1

AgIO₃ <=> Ag⁺ + IO₃^-

1 - 1.78*10^-4 1.78*10-4 1.78*10-4

$K_c = ~\dfrac {[Ag^+][IO_3^-]}{[AgIO_3]}=~\dfrac {(1.78*10^{-4})^2}{1-1.78*10^{-4}}=~ 3.17*~10^{-8}$

Answer: 3.17*10^-8