Answer to Question #321529 in General Chemistry for Srbrry

Question

A gas occupies a volume of 400.0 ml at 29⁰C and 1.15 atm if the pressure is held constant by how much should the temperature be decreased so that the volume decreases to 361.6 ml

Answer 1

Given:

V₁ = 400.0 mL

T₁ = 29°C + 273.15 = 302.15 K

P₁ = P₂ = 1.15 atm = constant

V₂ = 361.6 mL

T₂ = unknown

Formula: V₁ / T₁ = V₂ / T₂

Solution:

Since the pressure and amount of gas remain unchanged, Charles's law can be used.

Charles's law can be expressed as: V₁ / T₁ = V₂ / T₂

V₁T₂ = V₂T₁

To find the resulting temperature, solve the equation for T₂:

T₂ = V₂T₁ / V₁

T₂ = (361.6 mL × 302.15 K) / (400.0 mL) = 273.14 K

T₂ = 273.14 K (or 0°C)

ΔT = T₁ − T₂ = 29°C − 0°C = 29°C

Therefore, the temperature should be decreased by 29°C

Answer: The temperature should be decreased by 29°C