Answer to Question #320802 in General Chemistry for Breezy

Question #320802

What is the [OH] in a solution that has a pH = 4.02?

Expert's answer

pH = -log₁₀ [H₃O⁺] = 4.02

pOH = 14 – pH = 14 – 4.02 = 9.98

pOH = -log₁₀ [OH^-] = 9.98

[OH^-] = 1.05 x 10^-10

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