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Answer to Question #320761 in General Chemistry for Zayzat
Question #320761
Calculate the amount of energy (in KJ) needed to heat 346 gram of liquid water from 0 °C to 182 °C. Assume that the specific heat of water is 4.184 J/g °C over the entire liquid range and the specific heat of stream is 1.99 J/g °C
Expert's answer
"Q= mCdT"
Q= 346× 4.184× 182
= 263474.85J/g ⁰C
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