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Answer to Question #320761 in General Chemistry for Zayzat

Question #320761

Calculate the amount of energy (in KJ) needed to heat 346 gram of liquid water from 0 °C to 182 °C. Assume that the specific heat of water is 4.184 J/g °C over the entire liquid range and the specific heat of stream is 1.99 J/g °C

1
Expert's answer
2022-03-31T00:28:04-0400

"Q= mCdT"

Q= 346× 4.184× 182

= 263474.85J/g ⁰C



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