Calculate the mass percent of carbon, nitrogen and oxygen in acetamide, C2H5NO
Molar mass of C = 12g/mol
Molar mass of H = 1g/mol
Molar mass of N = 14g/mol
Molar mass of O = 16g/mol
Molar mass of C2H5NO = (12*2)+(1*5)+14+16 = 59g/mol
Mass percent of C = (2(12)/59)*100% = 40.7%
Mass percent of H = (1(5)/59)*100% = 8.5%
Mass percent of N = (14/59)*100 = 23.7%
Mass percent of O = (16/59)*100 = 27.1%
Note: make sure the percentages always add up to 100%
40.7+8.5+23.7+27.1= 100%
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