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Answer to Question #319822 in General Chemistry for Damien
Question #319822
what is the ph of a 0.210 m solution of acetic acid? ka= 1.75x10 -5
Expert's answer
"pH = pKa + log(1)"
PH= 1.75× 10^-5 + log(0.210)
pH= 1.75+ 0.68= 2.43
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