Question #319822

what is the ph of a 0.210 m solution of acetic acid? ka= 1.75x10 -5

Expert's answer

pH=pKa+log(1)pH = pKa + log(1)

PH= 1.75× 10^-5 + log(0.210)

pH= 1.75+ 0.68= 2.43



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