Answer to Question #319819 in General Chemistry for mike

Question

Use the balanced equation to answer the following question. One Pansit has a mass of 5.0 grams and one Siling Labuyo has a mass of 1.0 gram. How many Hot Pansit can be made from 40.0 grams of Pansit and 26.0 grams of Siling Labuyo? (Show your solution)

Answer 1

If the equation will look like this:

1*Pansit + 5*Siling Labuyo = 1*Hot Pansit;

Then, n(Pansit) = n(Hot Pansit) = 1;

n(Siling Labuyo) = 5;

m(Pansit) = 40.0 g;

m(Siling Labuyo) = 26.0 g;

m(Pansit)' = m(Pansit)/n(Pansit) = 40.0/1 = 40.0 g;

m(Siling Labuyo)' = m(Siling Labuyo)/n(Siling Labuyo) = 26.0/5 = 5.2 g.

So, the Pansit is excess and the Siling Labuyo is the limited reactant.

By the balanced equation:

m(Hot Pansit) = 1/5 * m(Siling Labuyo) = 1/5 * 26 = 5.2 g.

Answer: 5.2 g.