A crucible containing an unknown mass of magnesium weighs 37,63 if the mass of the empty crucible was found to be 32,83.determine the number of moles of magnesium
m(Mg) = 37.63 - 32.83 = 4.8 g
n(Mg) = m(Mg)/Mr(Mg) = 4.8 g / 24 g/mol = 0.2 mol
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment