B. A sample of neon gas at a pressure of 0.996 atm and a temperature of 28.9 °C, occupies a volume of 18.5 liters. If the gas is allowed to expand at constant temperature to a volume of 25.7 liters, the pressure of the gas sample will be ______ atm.
P1 = 0.996 atm
V1 = 18.5 L
T1 = T2 = 28.9°C = constant
P2 = ???
V2 = 25.7 L
Solution:
Since the temperature and amount of gas remain unchanged, Boyle's law can be used.
Boyle's gas law can be expressed as: P1V1 = P2V2
To find the new pressure, solve the equation for P2:
P2 = P1V1 / V2
P2 = (0.996 atm × 18.5 L) / (25.7 L) = 0.717 atm
P2 = 0.717 atm
Answer: The pressure of the gas sample will be 0.717 atm
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