A gaseous hydrocarbon, in a volume of 23.4 L at 392 K and a pressure of 3.16 atm, reacts in an excess of oxygen to give 165.7 g of H2O and 404.7 g of CO2. Determine the molecular formula of the hydrocarbon
The mass of CO2 produced is 404.7g and molar mass of CO2is44.0g/mol .
Calculate the moles of carbon as follows:
mol C= 404.7g CO2×1/44.010×1/1
=9.196mol
The mass of H2O produced is 165.7g and molar mass of is 18.015g/mol .
Calculate the moles of hydrogen as follows:
mol H=82.8×1/18.015×2/1
=9.19mol
Since the moles of both are the same, the ratio is 1:1. So the empirical formula is CH
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