5. What is the mass percent sucrose in a solution made by combining 365 g of a 8.90 percent sucrose by mass aqueous solution with 145 g of an 6.80 percent sucrose by mass aqueous solution? (5 points)
m(solution)1 = 365 g;
X(sucrose)1 = 8.90 %;
m(solution)2 = 145 g;
X(sucrose)2 = 6.80 %;
m(sucrose)1 = m(solution)1 * X(sucrose)1/100 = 365 * 8.90/100 = 32.485 g;
m(sucrose)2 = m(solution)2 * X(sucrose)2/100 = 145 * 6.80/100 = 9.860 g;
m(sucrose)total = m(sucrose)1 + m(sucrose)2 = 32.485 + 9.860 = 42.345 g;
m(solution)total = m(solution)1 + m(solution)2 = 365 + 145 = 510 g;
X(sucrose)total = m(sucrose)total/m(solution)total = 42.345/510 = 0.0830 = 8.30 %.
Answer: 8.30 %.
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