Answer to Question #319152 in General Chemistry for Jejemon

Question

what is the molarity of 3.0 moles of NaCl dissolved in 2000 g of water has a concentration of 1.5 m NaCl water solution.

Answer 1

Molarity of solution =

(mole of solute) /(Volume of solution in liters). _________(1)

First we calculate volume of solution in liters

Volume of solution in liters=

[(mole)/(mole/liters)] ____(2) of solution

Given : concentration of 1.5m of solution = 1.5 mol/lit

Mole of solution= mole of NaCl + mole of water

Mole of water = wt/ mol. Wt = 2000gm/18gm/mol=111.11mol

Mole of solution= 3 mole + 111.11mol

= 114.11 mol

Volume of solution in liters=

[(mole)/(mole/liters)] ____(2) of solution

Volume of solution in liters=

=(114.11 mol)/(1.5 mol/lit)

= 76.07 lit

Molarity of solution =

(mole of solute) /(Volume of solution in liters). _________(1)

Molarity of solution= 3mole/76.07lit

= 0.0394mol/lit