Question

Calculate the volume, in mL, of 1.72 M HCl solution that will react with 2.67 mol of CaCO3?

HCI + CaCO3 ---> CaCl2 + H2O + CO2

Answer 1

C(HCl) = 1.72 M;

n(CaCO₃) = 2.67 mol;

2HCI + CaCO₃ ---> CaCl₂ + H₂O + CO₂;

For following chemical reaction:

n(HCl) = 2 * n(CaCO₃) = 2 * 2.67 = 5.34 mol;

C(HCl) = n(HCl)/V(HCl);

V(HCl) = n(HCl)/C(HCl) = 5.34/1.72 = 3.105 L = 3105 mL.

Answer: 3105 mL.