Question

Chlorine trifluoride is a colorless, poisonous, and corrosive gas. It is produced from the reaction between chlorine fluoride and fluorine gas.

CIF(g) + F2 (g) → CLF3 (9)

Determine the ∆H° for the overall reaction based on the three-step thermochemical process below:

1.) 2CLF(g) + O2(g) → Cl₂0(g) + F₂0 (g) ∆°H-167.5 k]

2.) 2C1F3(g) +202(g) → Cl₂0(g) + 3F₂0(g)

∆H° =-341.4 k]

3.) 3F₂0)→2F2 (g) + O2(g)

∆H° = 43.4 kJ

Answer 1

$\Delta H°= (\Delta H_1- \Delta H_2 - \Delta H_3)/2$

$\Delta H°=(-167.5+341.4-43.4)/2=65.25$