What is the number of moles of NaCl in 3 litres of 3 M solution
Molarity of solution = 3 M
Volume of solution = 3 L
Molarity=moleVolume(inL)Molarity= \frac{mole}{Volume(inL)}Molarity=Volume(inL)mole
Mole = Molarity×volumeMolarity\times volumeMolarity×volume
mole = 9
So, mole of NaCl in 3 L of 3M solution is 9.
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