Question

A student needs to react 0.282 mol Zn with hydrochloric acid. Calculate the minimum number of moles of HCl required, assuming all the zinc reacts?

Answer 1

Zn + 2HCl --> ZnCl₂ + H₂

$n(HCl)=0.282\ mol(Zn)×\frac{2\ mol(HCl)}{1\ mol(Zn)}=0.564\ mol$

Answer: 0.564 mol