A student needs to react 0.282 mol Zn with hydrochloric acid. Calculate the minimum number of moles of HCl required, assuming all the zinc reacts?
Zn + 2HCl --> ZnCl2 + H2
"n(HCl)=0.282\\ mol(Zn)\u00d7\\frac{2\\ mol(HCl)}{1\\ mol(Zn)}=0.564\\ mol"
Answer: 0.564 mol
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