Answer to Question #316880 in General Chemistry for dkelgme

Question

How many grams of aluminum are needed to react with 2.08 kg of iron oxide?

Answer 1

• Write an equation: 2Al+3FeO---> Al2O3 + 3Fe
• Convert 2.08kg into moles 72g =1mole, what about 2080g
• 2080*1/72=28.8889moles
• Find equivalent moles of Al by mole ratio
• Al:FeO=2:3
• If ratio 3=28.8889moles, what about ratio 2.
• 2*28.8889/3=19.2593moles
• Convert to mass
• 27g = 1 mole, what about 19.2593moles
• 19.2593*27 = 520g