Question #316880
How many grams of aluminum are needed to react with 2.08 kg of iron oxide?
Expert's answer
- Write an equation: 2Al+3FeO---> Al2O3 + 3Fe
- Convert 2.08kg into moles 72g =1mole, what about 2080g
- 2080*1/72=28.8889moles
- Find equivalent moles of Al by mole ratio
- Al:FeO=2:3
- If ratio 3=28.8889moles, what about ratio 2.
- 2*28.8889/3=19.2593moles
- Convert to mass
- 27g = 1 mole, what about 19.2593moles
- 19.2593*27 = 520g
