How many grams of hydrochloric acid are needed to react with 20 g of calcium carbonate?
m(CaCO3) = 20 g;
M(CaCO3) = 100 g/mol;
M(HCl) = 36.5 g/mol;
n(CaCO3) = m(CaCO3)/M(CaCO3) = 20/100 = 0.2 mol;
2HCl + CaCO3 = CaCl2 + CO2 + H2O;
For chemical reaction:
n(HCl) = 2 * n(CaCO3) = 2 * 0.2 = 0.4 mol;
m(HCl) = n(HCl) * M(HCl) = 0.4 * 36.5 = 14.6 g.
Answer: 14.6 g.
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