Answer to Question #316875 in General Chemistry for Hello

Question

How many grams of iron oxide is produced by the reaction of 120g of pyrite with sufficient oxygen

Answer 1

Pyrite = FeS₂;

4FeS₂ + 11O₂ = 2Fe₂O₃ + 8SO₂;

For chemical reaction:

n(Fe₂O₃) = 2/4 * n(FeS₂) = 1/2 * n(FeS₂);

m(FeS₂) = 120 g;

M(FeS₂) = 120 g/mol;

n(FeS₂) = m(FeS₂)/M(FeS₂) = 120/120 = 1 mol;

n(Fe₂O₃) = 1/2 * n(FeS₂) = 1/2 mol = 0.5 mol;

M(Fe₂O₃) = 160 g/mol;

m(Fe₂O₃) = n(Fe₂O₃) * M(Fe₂O₃) = 0.5 * 160 = 80 g.

Answer: 80 g.