Answer to Question #316498 in General Chemistry for Autumn123

Question

Calculate the volume, in mL, of 1.72 M HCl solution that will react with 2.67 mol of CaCO3?

Answer 1

CaCO₃ + 2HCl ----- CaCl₂ + H₂CO₃

From the equation,

1 mol of CaCO₃ reacts with 2 mol of HCl

2.67 mol of CaCO₃ will react with (2.67*2) mol of HCl = 5.34 mol of HCl

Molarity = mol/volume in L

1.72 = 5.34/V

V = 5.34/1.72 = 3.10L = 3100mL