Question #316421

2.00 kJ of heat flowed to a 103 g sample of a liquid solvent, causing a temperature increase from 15.15 °C to 21.49 °C. The specific heat capacity of the liquid

1
Expert's answer
2022-03-24T00:16:03-0400

Q=m.c.dtQ= m.c.dt

2000= 103× c× 6.34

C= 3.04 J.g


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