Answer to Question #316196 in General Chemistry for LOIGG

Question

The solubility of a gas is 4.5 g/l at a pressure of 1.0 atm. At what pressure will there be solubility of 45 g/l

Answer 1

According to Henry's law:

$\frac{S1}{P1}=\frac{S2}{P2}$

S1-4.5g/l

P1-1.0atm

P2-?

S2-45g/l

$\therefore P2=P1×S2÷S1$

$=\frac{1.0atm\times 45g/l}{4.5g/l}=10atm$