Answer to Question #315629 in General Chemistry for John Benedict

Question

how many joules are required to heat 69g of water(liquid) from 69c to 96 c

Answer 1

We apply the formula

q = mc$\Delta$T

Where m is the mass of water = 69/1000kg

c is the specific heat capacity of water = 4182J/kg^oC

$\Delta$T is the change in temperature = 96-69=27^oC

q = 0.069kg x 4182J/kg^oC x 27^oC = 7791.066J