Answer to Question #315151 in General Chemistry for Goya

Question

how could you make a 7.8% aqueous solution of glucose using 5.0g of glucose?

Answer 1

Let x be mass of water

$\omega(glucose)=\dfrac{mass\ of\ glucose}{mass\ of\ solution}=\dfrac{5.0\ g}{5.0+x\ g}=0.078$

$5.0*0.078+0.078x=5.0$

$0.078x=5.0-5.0*0.078=4.61$

$x=\dfrac{4.61}{0.078}=59.1\ g$

Answer: add 59.1 g of water