A hot air balloon can contain upwards of 16,000 L of gas (at STP)
how many combined molecules/atoms of air will be present?
n=VVm=1600022.4=714.29n=\frac{V}{Vm}=\frac{16000}{22.4}=714.29n=VmV=22.416000=714.29 mol
N=N(A)×n=714.29×6×1023=4285.71×1023N=N(A)\times n=714.29\times6\times10^{23}=4285.71\times10^{23}N=N(A)×n=714.29×6×1023=4285.71×1023
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