Answer to Question #314628 in General Chemistry for Ivan Ackerman

Question

The reaction goes to completion, but in the process of recovering the product, some of it was lost. The the percent yield for the reaction is 82.2%.

82.2%. How many grams of product are recovered?

mass of product recovered:

How many grams of the excess reactant remain? Assume the reaction goes to completion.

mass of excess reactant:

Answer 1

2KClO₃→2KCl+3O₂

From the reaction,it can be seen that;

2mol of KClO₃= 3mol of O₂

1 mol of KClO₃=3/2 mol O₂

=1.5 mol O₂

The yield of the reaction is given in % i.e 82.2%

1 mil KClO₃ generates 1.5 mol O₂

Since the yield is 82.2%,the number of moles of O₂ generated per mole of KClO₃ is

1.5mol×82.2/100=1.233mol

Number of moles ofO₂=42.0g/32.0g

=1.31 mol.

Number of moles of KClO₃

=1.31mol O₂/1.233 mol O₂/KClO₃

=1.615mol KClO₃

Weight of KClO₃=1.35 mol KClO₃×molecular weight of KClO₃

=1.615×112.6g

=182g