Consider the following equation:
Ca(OH)2(s) + 2 HCl(aq) —> CaCl2(aq) + 2 H2O(l)
a) How many liters of 0.100 M HCl is required to completely react with 5.00 grams of calcium hydroxide?
b) If 15.0 grams of calcium hydroxide is combined with 75.0 mL of 0.500 M HCl, how many grams of calcium chloride
would be formed?
Moles of calcium hydroxide
Moles= 5/74= 0.0676
(0.0676/0.5)× 1000= 135ml
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