Answer to Question #314525 in General Chemistry for Nel

Question

In the commercial preparation of Hydrogen Chloride, what weight of HCl in grams may be obtained by heating 468 grams of NaCl with H2S04.

2NaCl + H2S04 􏰀 NaSO4 + 2HCl

Answer 1

$m(HCl)=468\ g(NaCl)\times\frac{1\ mol(NaCl)}{58.44\ g(NaCl)}\times\frac{2\ mol(HCl)}{2\ mol(NaCl)}\times\frac{36.46\ g(HCl)}{1\ mol(HCl)}=292\ g$

Answer: 292 g