How many moles of O2 are needed to react with 2.83 moles
n(H2O) = 2.83 moles.
Solution:
The equation of a chemical reaction:
4NO2(g) + 6H2O(g) → 7O2(g) + 4NH3(g)
According to the reaction equation: n(NO2)/4 = n(H2O)/6.
n(NO2) = 4*n(H2O)/6;
n(NO2) = (4 * 2.83 moles) / 6 = 1.8867 moles = 1.89 moles
n(NO2) = 1.89 moles.
Answer: 1.89 moles of nitrogen dioxide (NO2).
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