1) Calculate the molarity of a 45.3 g NaNO3 dissolved in water to produce 225 mL of solution.
2) What mass of concentrated HCl is needed to prepare 2.45 L of 13.0 M HCl?
3) What volume can be prepared from 1.0 M NaOH from 2.54 g NaOH?
1)Molarity= moles/ litre
Moles= 45.3/85= 0.5329
Molarity= 0.53M
2)mass= moles× rmm
Moles=( 2.45/1)×13= 31.85
Mass= 31.85× 36.5= 1162.5g
3)moles= 2.54/ 40= 0.0635
If 1.0 moles are in a litre then
(0.0635/1)× 1000= 63.5ml
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